The ratio of `p_(pi)-d_(pi)` bonds is `SO_(2) and SO_(3)` molecules 

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `2:3`

Answer

To determine the ratio of pπ-dπ bonds in SO₂ and SO₃ molecules, we will analyze the bonding in each molecule step by step.

### Step 1: Analyze the structure of SO₂
1. **Lewis Structure**: SO₂ has a bent structure with one sulfur atom double bonded to two oxygen atoms.
2. **Hybridization**: The hybridization of sulfur in SO₂ is sp².
3. **Bond Formation**:
- Each oxygen forms a double bond with sulfur, which consists of one sigma (σ) bond and one pi (π) bond.
- The π bond between sulfur and oxygen is a pπ-pπ bond.

### Step 2: Count the pπ-dπ bonds in SO₂
1. In SO₂, there are no d orbitals involved in bonding since sulfur uses its p orbitals to form bonds with oxygen.
2. Therefore, the number of pπ-dπ bonds in SO₂ is **0**.

### Step 3: Analyze the structure of SO₃
1. **Lewis Structure**: SO₃ has a trigonal planar structure with one sulfur atom double bonded to three oxygen atoms.
2. **Hybridization**: The hybridization of sulfur in SO₃ is sp².
3. **Bond Formation**:
- Each oxygen forms a double bond with sulfur, which consists of one sigma (σ) bond and one pi (π) bond.
- The π bonds between sulfur and oxygen are pπ-pπ bonds.

### Step 4: Count the pπ-dπ bonds in SO₃
1. In SO₃, sulfur can utilize its d orbitals to form bonds with oxygen.
2. Each double bond consists of one pπ-pπ bond and one pπ-dπ bond.
3. Therefore, for the three oxygen atoms, there are **3 pπ-dπ bonds** in SO₃.

### Step 5: Calculate the ratio of pπ-dπ bonds in SO₂ and SO₃
1. From the previous steps:
- SO₂ has **0 pπ-dπ bonds**.
- SO₃ has **3 pπ-dπ bonds**.
2. The ratio of pπ-dπ bonds in SO₂ to SO₃ is:
\[ \text{Ratio} = \frac{0}{3} = 0:3 \text{ or simplified to } 0:1 \]

### Final Answer
The ratio of pπ-dπ bonds in SO₂ and SO₃ is **0:3**, which can be simplified to **0:1**.

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