Bond angle, bond length and hybridisation in `SO_(3)` molecule respectively are

Options

A. `119.5^(@)," 143 nm, "sp^(2)`
B. `119.5^(@)," 143 pm, "sp^(2)`
C. `119.5^(@)," 143 pm, "sp^(3)`
D. `119.5^(@)," 143 pm, "sp^(3)d`

Answer

To determine the bond angle, bond length, and hybridization in the SO₃ molecule, we can follow these steps:

### Step 1: Determine the Lewis Structure of SO₃
- Sulfur (S) is the central atom, and it forms double bonds with three oxygen (O) atoms.
- The Lewis structure can be represented as:
```
O
||
O = S = O
```

### Step 2: Calculate the Steric Number
- The steric number (SN) is calculated using the formula:
\[ \text{Steric Number} = \text{Number of Lone Pairs} + \text{Number of Sigma Bonds} \]
- For sulfur in SO₃:
- Number of lone pairs = 0 (sulfur has no lone pairs in this structure)
- Number of sigma bonds = 3 (one sigma bond for each S=O double bond)
- Therefore, the steric number is:
\[ \text{SN} = 0 + 3 = 3 \]

### Step 3: Determine Hybridization
- Based on the steric number:
- If SN = 3, the hybridization is sp².
- Thus, the hybridization of SO₃ is sp².

### Step 4: Determine Bond Angle
- In an sp² hybridized molecule, the bond angle is approximately 120°.
- Therefore, the bond angle in SO₃ is 120°.

### Step 5: Determine Bond Length
- The bond length in SO₃ for S=O double bonds is typically around 1.40 Å (angstroms).

### Final Answer:
- The bond angle, bond length, and hybridization in SO₃ are:
- Bond Angle: 120°
- Bond Length: ~1.40 Å
- Hybridization: sp²

### Summary:
- Bond Angle: 120°
- Bond Length: ~1.40 Å
- Hybridization: sp²