In `gamma`-form of `SO_(3)`, the hybridisation of sulphur is

Options

A. `sp`
B. `sp^(3)d`
C. `sp^(2)`
D. `sp^(3)`

Answer

To determine the hybridization of sulfur in the gamma form of \( SO_3 \), we can follow these steps:

### Step 1: Understand the Structure of Gamma Form of \( SO_3 \)
The gamma form of \( SO_3 \) refers to the solid state of sulfur trioxide, which has a cyclic structure. In this structure, sulfur is surrounded by oxygen atoms in a specific arrangement.

**Hint:** Recall that the gamma form of \( SO_3 \) is a solid with a cyclic structure.

### Step 2: Identify the Bonds in the Structure
In the cyclic structure of \( SO_3 \), sulfur forms:
- 4 sigma bonds with oxygen atoms.
- There are no lone pairs on the sulfur atom.

**Hint:** Count the number of sigma bonds and lone pairs around the sulfur atom.

### Step 3: Calculate the Steric Number
The steric number can be calculated using the formula:
\[ \text{Steric Number} = \text{Number of Lone Pairs} + \text{Number of Sigma Bonds} \]
For sulfur in this case:
- Number of lone pairs = 0
- Number of sigma bonds = 4

Thus, the steric number is:
\[ \text{Steric Number} = 0 + 4 = 4 \]

**Hint:** Remember that the steric number is the sum of lone pairs and sigma bonds.

### Step 4: Determine the Hybridization
Using the steric number, we can determine the hybridization:
- A steric number of 4 corresponds to \( sp^3 \) hybridization.

**Hint:** Use the correlation between steric number and hybridization to identify the correct hybridization type.

### Conclusion
The hybridization of sulfur in the gamma form of \( SO_3 \) is \( sp^3 \).

**Final Answer:** The hybridization of sulfur in the gamma form of \( SO_3 \) is \( sp^3 \).