In the tailing of mercury ozone oxidises X to Y, X and Y are respectively 

Options

A. `Hg, Hg(I)O`
B. `Hg, Hg(II)O`
C. `Hg(I)O, Hg(II)O`
D. `Hg(II)O, He(I)O`

Answer

To solve the problem, we need to identify the substances X and Y that are involved in the reaction where mercury (Hg) is oxidized by ozone (O3).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this reaction is mercury (Hg) and ozone (O3).

2. **Determine the Reaction**:
- Ozone (O3) acts as an oxidizing agent. When it reacts with mercury, it oxidizes mercury to a higher oxidation state.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ 2 \text{Hg} + \text{O}_3 \rightarrow \text{Hg}_2\text{O}_2 \]
- Here, mercury (Hg) is oxidized to mercury(II) oxide (Hg2O2).

4. **Identify X and Y**:
- In this reaction, X is the starting material (Hg) and Y is the product formed (Hg2O2).
- Therefore, we can conclude:
- \( X = \text{Hg} \)
- \( Y = \text{Hg}_2\text{O}_2 \)

5. **Determine Oxidation States**:
- In elemental mercury (Hg), the oxidation state is 0.
- In mercury(II) oxide (Hg2O2), the oxidation state of mercury is +1.

6. **Final Answer**:
- Thus, X and Y are respectively:
- \( X = \text{Hg} \)
- \( Y = \text{Hg}_2\text{O}_2 \)

### Conclusion:
The final answer is:
- \( X = \text{Hg} \)
- \( Y = \text{Hg}_2\text{O}_2 \)