Eventhough `Cu^(2+)` has one unpaired d - electron, anhydrous copper sulphate is colourless. Why?

Explanation

To understand why anhydrous copper sulfate (CuSO₄) is colorless despite the presence of one unpaired d-electron in Cu²⁺, we can break down the explanation into several steps:

### Step-by-Step Solution:

1. **Understanding the Electron Configuration of Copper:**
- Copper (Cu) has the atomic number 29, and its electron configuration is [Ar] 4s² 3d⁹ in the neutral state.
- When copper loses two electrons to form Cu²⁺, the electron configuration becomes [Ar] 3d⁹ (the 4s electrons are removed before the 3d electrons).

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