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Non-stoichiometric compounds are...

Non-stoichiometric compounds are

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Assertion (A) : Non-stoichiometric compounds are called Bertholide compounds. NaCl and KCl crystal, when heated in an atmosphere of Na and K varpours, respectively, they impart violet and yellow colours to NaCl and KCl , respectively. Reason (R ) : Metal excess defect is due to the presence of extra cations atg the interstitial sites. The excess metal ions move to the interstitial sites and the electrons to the neighbouring sites. The colour results byt the excitation of these electrons by absorbing suitable energy from visible light. When the excited electroon comes back to the ground state, there is emission of radiation in the visible region and gives complimentary colour.

The non- stoichiometric compound Fe_(0.94)O is formed when x% of Fe^(2+) ions are replaced by as many 2//3 Fe^(3+) ions The value of x is:

The non-stoichiometric compound Fe_0.94O is formed when some Fe^(+2) ions are replaced by Fe^(+3) ions. What is the percentage of Fe^(+3) ions in this ionic lattice ?

1.44 gram if titanium (Ti) reacted with excess of O_(2) and produce x gram of non - stoichiometric compound Ti_(1.44)O . The value of x is :

1, 44 gran if tutanium (Ti) reacted with excess of O_(2) and produce x gram of non - stoichiometric compound Ti_(1.44)O . The value of x is :

1.44 gram of Titanium (Ti) reacted with excess of O_(2) and produced x gram of non-stoichiometric compound Ti ._(0.44)O . The value of x will be :[Ti = 48]

Non-stoichiometric cuprous oxide. Cu_(2)O can be perpared in laboratory. In this oxide, copper-to-oxygen ratio is slightly less than 2 : 1. can you account for the fact that this substance is a p-type semiconductors?

Non-stoichiometric cuprous oxide. Cu_(2)O can be perpared in laboratory. In this oxide, copper-to-oxygen ratio is slightly less than 2 : 1. can you account for the fact that this substance is a p-type semiconductors?

Non-stoichiometric hydrides are formed by

Analyses shows that FeO has a non-stoichiometric composition with formula Fe_(0.95)O_(1.00) . Give reason.