The transition element that has stable configuration in `+1` oxidation state is

Options

A. Cu
B. Zn
C. Sc
D. Mn

Answer

To determine which transition element has a stable configuration in the +1 oxidation state, we will analyze the electronic configurations of the given options: copper, zinc, scandium, and manganese.

### Step-by-Step Solution:

1. **Identify the Atomic Numbers and Electronic Configurations:**
- **Copper (Cu)**: Atomic number = 29
- Electronic configuration: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1, 3d^{10}\)
- **Zinc (Zn)**: Atomic number = 30
- Electronic configuration: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2\)
- **Scandium (Sc)**: Atomic number = 21
- Electronic configuration: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^3\)
- **Manganese (Mn)**: Atomic number = 25
- Electronic configuration: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^2\)

2. **Determine the +1 Oxidation State Configurations:**
- **Copper (Cu)**:
- In +1 oxidation state (Cu\(^+\)), it loses one electron from the 4s orbital:
- Configuration: \(3d^{10}\) (stable configuration)
- **Zinc (Zn)**:
- In +1 oxidation state (Zn\(^+\)), it loses one electron from the 4s orbital:
- Configuration: \(3d^{10}, 4s^1\) (not stable, as it prefers to lose both 4s electrons to become Zn\(^2+\))
- **Scandium (Sc)**:
- In +1 oxidation state (Sc\(^+\)), it loses one electron from the 3d orbital:
- Configuration: \(3d^2\) (not stable)
- **Manganese (Mn)**:
- In +1 oxidation state (Mn\(^+\)), it loses one electron from the 4s orbital:
- Configuration: \(3d^5, 4s^1\) (not stable)

3. **Conclusion:**
- Among the elements analyzed, only **Copper (Cu)** has a stable electronic configuration in the +1 oxidation state, which is \(3d^{10}\).

### Final Answer:
The transition element that has a stable configuration in the +1 oxidation state is **Copper (Cu)**.