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When KMnO(4) reacts with acidified FeSO(...

When `KMnO_(4)` reacts with acidified `FeSO_(4)`

A

Both `FeSO_(4)` and `KMnO_(4)` are oxidised

B

Both `FeSO_(4)` and `KMnO_(4)` are reduced

C

`FeSO_(4)` is oxidised and `KMnO_(4)` is reduced

D

`FeSO_(4)` is reduced and `KMnO_(4)` is oxidised

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction between KMnO4 and acidified FeSO4, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants in this reaction are potassium permanganate (KMnO4) and acidified iron(II) sulfate (FeSO4). The acidification is typically done using sulfuric acid (H2SO4). 2. **Determine the Oxidation States**: - In KMnO4, manganese (Mn) has an oxidation state of +7. - In FeSO4, iron (Fe) has an oxidation state of +2. 3. **Identify the Reaction Type**: This is a redox reaction where one species is oxidized and another is reduced. KMnO4 is known to be a strong oxidizing agent. 4. **Oxidation and Reduction**: - **Oxidation**: The Fe^2+ ions in FeSO4 will lose electrons and get oxidized to Fe^3+ ions. - **Reduction**: The MnO4^- ions in KMnO4 will gain electrons and get reduced to Mn^2+ ions. 5. **Write the Half-Reactions**: - Oxidation half-reaction: \[ \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + e^- \] - Reduction half-reaction: \[ \text{MnO}_4^- + 8 \text{H}^+ + 5 e^- \rightarrow \text{Mn}^{2+} + 4 \text{H}_2\text{O} \] 6. **Combine the Half-Reactions**: To balance the electrons transferred, multiply the oxidation half-reaction by 5: \[ 5 \text{Fe}^{2+} \rightarrow 5 \text{Fe}^{3+} + 5 e^- \] Now, combine it with the reduction half-reaction: \[ \text{MnO}_4^- + 8 \text{H}^+ + 5 e^- \rightarrow \text{Mn}^{2+} + 4 \text{H}_2\text{O} \] 7. **Overall Reaction**: The overall balanced reaction can be written as: \[ \text{MnO}_4^- + 8 \text{H}^+ + 5 \text{Fe}^{2+} \rightarrow \text{Mn}^{2+} + 4 \text{H}_2\text{O} + 5 \text{Fe}^{3+} \] 8. **Conclusion**: In this reaction, FeSO4 is oxidized to Fe^3+, and KMnO4 is reduced to Mn^2+. Therefore, the correct answer to the question is that FeSO4 is oxidized and KMnO4 is reduced. ### Final Answer: FeSO4 is oxidized and KMnO4 is reduced.
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