When `Na_(2)CrO_(4)`, is dissolved in sulphuric acid, it changes to

Options

A. orange coloured `Na_(2)Cr_(2)O_(7)`
B. yellow coloured `Na_(2)Cr_(2)O_(7)`
C. retains as orange coloured `Na_(2)CrO_(4)`
D. retains as yellow coloured `Na_(2)CrO_(4)`

Answer

To solve the question regarding the reaction of sodium chromate (\(Na_2CrO_4\)) when dissolved in sulfuric acid (\(H_2SO_4\)), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are sodium chromate (\(Na_2CrO_4\)) and sulfuric acid (\(H_2SO_4\)).

2. **Write the Reaction**:
When sodium chromate is dissolved in sulfuric acid, it undergoes a chemical reaction. The balanced reaction can be written as:
\[ Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O \]

3. **Identify the Products**:
The products of this reaction are sodium dichromate (\(Na_2Cr_2O_7\)), sodium sulfate (\(Na_2SO_4\)), and water (\(H_2O\)).

4. **Determine the Color Change**:
Sodium chromate (\(Na_2CrO_4\)) is typically yellow in color, while sodium dichromate (\(Na_2Cr_2O_7\)) is orange in color. Thus, when \(Na_2CrO_4\) is dissolved in sulfuric acid, it changes to an orange-colored solution due to the formation of \(Na_2Cr_2O_7\).

5. **Conclusion**:
Therefore, the final answer to the question is that when \(Na_2CrO_4\) is dissolved in sulfuric acid, it changes to sodium dichromate (\(Na_2Cr_2O_7\)), which is orange in color.

### Final Answer:
When \(Na_2CrO_4\) is dissolved in sulfuric acid, it changes to \(Na_2Cr_2O_7\) (orange color).

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