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Oxidation number of chromium in chromyl ...

Oxidation number of chromium in chromyl chloride is

A

`+2`

B

`+3`

C

`+4`

D

`+6`

Text Solution

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The correct Answer is:
To determine the oxidation number of chromium in chromyl chloride (CrO2Cl2), we can follow these steps: ### Step 1: Write the formula of chromyl chloride. The formula for chromyl chloride is CrO2Cl2. ### Step 2: Assign oxidation states to the known elements. - Oxygen (O) typically has an oxidation state of -2. - Chlorine (Cl) typically has an oxidation state of -1. ### Step 3: Set up the equation for the oxidation number of chromium. Let the oxidation number of chromium be represented as \( x \). ### Step 4: Calculate the total contribution from oxygen and chlorine. - There are 2 oxygen atoms, contributing a total of \( 2 \times (-2) = -4 \). - There are 2 chlorine atoms, contributing a total of \( 2 \times (-1) = -2 \). ### Step 5: Write the equation for the overall charge. Since chromyl chloride is a neutral molecule, the sum of the oxidation states must equal 0. Therefore, we can write the equation: \[ x + (-4) + (-2) = 0 \] ### Step 6: Simplify the equation. This simplifies to: \[ x - 6 = 0 \] ### Step 7: Solve for \( x \). Adding 6 to both sides gives: \[ x = +6 \] ### Conclusion: The oxidation number of chromium in chromyl chloride (CrO2Cl2) is +6. ---
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