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The actinide element which can exhibit +...

The actinide element which can exhibit `+7` oxidation state in its compounds

A

Thorium

B

Curium

C

Neptunium

D

Nobelium

Text Solution

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The correct Answer is:
To determine which actinide element can exhibit a +7 oxidation state in its compounds, we can analyze the oxidation states of the given options: thorium, curium, neptunium, and nobelium. ### Step-by-Step Solution: 1. **Identify the Actinide Elements**: The actinide series includes elements from actinium (Ac, atomic number 89) to lawrencium (Lr, atomic number 103). The elements in the question are thorium (Th), curium (Cm), neptunium (Np), and nobelium (No). 2. **Examine the Oxidation States**: - **Thorium (Th)**: The common oxidation state of thorium is +4. It does not exhibit a +7 oxidation state. - **Curium (Cm)**: Curium typically shows oxidation states of +3 and +4. It does not exhibit a +7 oxidation state. - **Neptunium (Np)**: Neptunium can exhibit a range of oxidation states, including +3, +4, +5, +6, and crucially, +7. Therefore, it can exhibit a +7 oxidation state. - **Nobelium (No)**: Nobelium generally shows an oxidation state of +3 and does not exhibit a +7 oxidation state. 3. **Conclusion**: Among the options provided, neptunium (Np) is the only actinide element that can exhibit a +7 oxidation state in its compounds. ### Final Answer: The actinide element which can exhibit a +7 oxidation state in its compounds is **Neptunium (Np)**. ---
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