Highest oxidation state exhibited by an actinide element in its compounds is

Options

A. `+4`
B. `+6`
C. `+7`
D. `+8`

Answer

To determine the highest oxidation state exhibited by an actinide element in its compounds, we can follow these steps:

### Step 1: Understand Actinides
Actinides are the series of elements that are found in the f-block of the periodic table. They range from actinium (Ac, atomic number 89) to lawrencium (Lr, atomic number 103). The general electronic configuration for actinides is [Rn] 5f^1 to 14 6d^0 to 1 7s^2.

**Hint:** Remember that actinides are f-block elements and have a specific range of atomic numbers.

### Step 2: Identify Oxidation States
The oxidation states of actinides can vary widely due to the involvement of the 5f, 6d, and 7s electrons in bonding. The common oxidation states for actinides include +3, +4, +5, and +6. However, some actinides can exhibit higher oxidation states.

**Hint:** Look for the common oxidation states of f-block elements, especially the actinides.

### Step 3: Determine the Highest Oxidation State
The highest oxidation state that can be exhibited by actinides is +7. This oxidation state is notably shown by elements such as plutonium (Pu) and neptunium (Np).

**Hint:** Focus on the specific actinides known for their maximum oxidation states, particularly plutonium and neptunium.

### Step 4: Conclusion
Thus, the highest oxidation state exhibited by an actinide element in its compounds is +7.

**Final Answer:** +7