Home
Class 12
CHEMISTRY
Assertion: Aquated copper(I) cation unde...

Assertion: Aquated copper(I) cation undergoes disproportionation as:
`2Cu^(+)(aq) to Cu^(2+)(aq)+Cu`
Reason: Hydration energy of `Cu^(2+)` is higher than that of `Cu^(+)` which compensates second ionisation energy of Cu.

A

Both A & R are true, R is the correct explanation of A

B

Both A & R are true, R is not correct explanation of A

C

A is true, R is false

D

A is false, R is true

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Why Cr and Cu have abnormally higher 2nd ionisation energy

The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Consider the following transformation: CuSO_(4)(aq.)+KI(excess)to product Select the correct statement:

Find the number of electrons transferred in the equation Cu(g) + 2Ag^+(aq) → Cu^(2+)(aq) + 2Ag(s) .

For the disproportion of copper: 2 Cu^(+) to Cu^(+2) + Cu E^(0) is :- Given E^(0) for Cu^(+2)//Cu is 0.34 V & E^(0) for Cu^(+2)//Cu^(+) is 0.15 V:

Assertion (A) Cu (II) iodide is not known. Reason (R ) Cu^(2+) oxidises I^(-) to iodine.

Write Nernst equation for the following cell reaction : Zn"|"Zn^(2+)(aq)"||"Cu^(2+)(aq)"|"Cu(s)

Assertion (A) Cu^(2+) iodide is not known. Reason (R ) Cu^(2+) oxidises I^(-) to iodine.

Assertion : Copper is unable to displace H_2 form dil. H_2 SO_4 Reason : The standard electrode potential for Cu^(2+)//Cu system is greater than that of H^+//1/2 H_2 system.

In Cu-ammonia complex the state of hybridization of Cu^(+2) is