Number of electrons present in the outer most shell of `Cu^+` ion 

Options

A. 0
B. 1
C. 8
D. 18

Answer

To determine the number of electrons present in the outermost shell of the `Cu^+` ion, we can follow these steps:

### Step 1: Determine the atomic number of copper (Cu).
Copper has an atomic number of 29, which means it has 29 electrons in its neutral state.

### Step 2: Write the electron configuration of neutral copper.
The electron configuration of neutral copper (Cu) is:
- 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s¹

### Step 3: Identify the outermost shell of neutral copper.
The outermost shell for copper is the 4th shell (n=4), which contains:
- 4s¹ (1 electron)

### Step 4: Determine the electron configuration of the `Cu^+` ion.
The `Cu^+` ion is formed when copper loses one electron. This electron is lost from the outermost shell (4s¹). Therefore, the electron configuration of `Cu^+` becomes:
- 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

### Step 5: Identify the outermost shell of the `Cu^+` ion.
For the `Cu^+` ion, the outermost shell is now the 3rd shell (n=3), which contains:
- 3s² 3p⁶ 3d¹⁰

### Step 6: Count the total number of electrons in the outermost shell of `Cu^+`.
In the 3rd shell, we have:
- 3s² (2 electrons)
- 3p⁶ (6 electrons)
- 3d¹⁰ (10 electrons)

Adding these together gives:
- 2 + 6 + 10 = 18 electrons

### Conclusion:
Therefore, the number of electrons present in the outermost shell of the `Cu^+` ion is **18**.