How many reductional divisions are required to form 400 synergids?

Options

A. 400
B. 300
C. 200
D. 100

Answer

To determine how many reductional divisions are required to form 400 synergids, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Process**:
- In the context of plant reproduction, synergids are formed during the development of the female gametophyte (embryo sac) in the ovule.
- Synergids are produced through meiotic divisions, which are reductional divisions that reduce the chromosome number from diploid (2n) to haploid (n).

2. **Meiosis and Synergids**:
- Each meiotic division results in the formation of four haploid cells from one diploid cell. However, in the case of synergids, only two of these cells (the synergids) are formed from one meiotic division.
- Therefore, one meiotic division can produce two synergids.

3. **Calculating the Number of Divisions**:
- To find out how many meiotic divisions are needed to produce 400 synergids, we can set up the equation:
\[ \text{Number of synergids} = 2 \times \text{Number of meiotic divisions} \]
- Rearranging this gives us:
\[ \text{Number of meiotic divisions} = \frac{\text{Number of synergids}}{2} \]
- Substituting the number of synergids (400):
\[ \text{Number of meiotic divisions} = \frac{400}{2} = 200 \]

4. **Conclusion**:
- Therefore, to form 400 synergids, **200 reductional divisions (meiotic divisions)** are required.

### Final Answer:
**200 reductional divisions are required to form 400 synergids.**

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