The ratio of chromosomes moving to each pole during Anaphase-II to those moving to each pole during Anaphase-I

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `1:4`

Answer

To solve the question regarding the ratio of chromosomes moving to each pole during Anaphase-II compared to those moving to each pole during Anaphase-I, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Meiosis**: Meiosis is a type of cell division that reduces the chromosome number by half, resulting in four haploid cells from one diploid cell. It consists of two main stages: Meiosis I and Meiosis II.

2. **Identify Anaphase I and Anaphase II**:
- **Anaphase I**: During this phase, homologous chromosomes (each consisting of two sister chromatids) are separated and move to opposite poles. Since the original cell is diploid (2n), two sets of chromosomes are moving to each pole.
- **Anaphase II**: In this phase, the sister chromatids of each chromosome are separated and move to opposite poles. At this point, the cell is haploid (n), meaning only one set of chromosomes is present.

3. **Count Chromosomes Moving to Each Pole**:
- In Anaphase I, if we start with a diploid cell (2n), there are n chromosomes moving to each pole (since homologous pairs are separated).
- In Anaphase II, since the cell is haploid (n), there is 1 chromosome (which consists of 2 sister chromatids) moving to each pole.

4. **Establish the Ratio**:
- The ratio of chromosomes moving to each pole during Anaphase II (1 chromosome) to those moving to each pole during Anaphase I (n chromosomes) is therefore 1:2.

5. **Select the Correct Option**: Based on the established ratio of 1:2, the correct answer from the given options is **1:2**.

### Final Answer:
The ratio of chromosomes moving to each pole during Anaphase-II to those moving to each pole during Anaphase-I is **1:2**.

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