Mitotic cell cycle is divided into 4 phases `G_(1)`, S `G_(2)` and M. Considering a mitotic cycle time of 18 hours the distributing of period of time (in hours) for each of these phases will most likely be

Options

A. `{:(G_(1),S,G_(2),M,),(1,3,5,9,):}`
B. `{:(G_(1),S,G_(2),M,),(9,1,3,5,):}`
C. `{:(G_(1),S,G_(2),M,),(9,5,3,1,):}`
D. `{:(G_(1),S,G_(2),M,),(3,4,9,1,):}`

Answer

To solve the question regarding the distribution of time for the phases of the mitotic cell cycle, we can break it down step by step:

### Step 1: Understand the Phases of the Cell Cycle
The mitotic cell cycle consists of four main phases:
- **G1 Phase (Gap 1)**: The cell grows and synthesizes proteins necessary for DNA replication.
- **S Phase (Synthesis)**: The cell replicates its DNA.
- **G2 Phase (Gap 2)**: The cell prepares for mitosis, ensuring all DNA is replicated and the cell is ready to divide.
- **M Phase (Mitosis)**: The actual division of the cell occurs.

### Step 2: Determine the Duration of Each Phase
Given that the total duration of the mitotic cycle is 18 hours, we need to allocate this time to each phase based on their relative lengths:
- G1 is the longest phase.
- S is the second longest, as it involves DNA replication.
- G2 is shorter than S but longer than M.
- M is the shortest phase, typically taking about 1 hour.

### Step 3: Estimate Time Distribution
Based on the understanding of the phases:
- **G1 Phase**: Approximately 9 hours (the longest phase).
- **S Phase**: Approximately 5 hours (longer than G2, as it involves DNA synthesis).
- **G2 Phase**: Approximately 3 hours (preparation for mitosis).
- **M Phase**: Approximately 1 hour (the shortest phase).

### Step 4: Summarize the Time Distribution
Thus, the most likely distribution of time for each phase in hours is:
- G1: 9 hours
- S: 5 hours
- G2: 3 hours
- M: 1 hour

### Final Answer
The distribution of time for each of the phases of the mitotic cell cycle, considering a total cycle time of 18 hours, is:
- G1: 9 hours
- S: 5 hours
- G2: 3 hours
- M: 1 hour