Arrangement of nuclei in normal dicot embryo sac is

Options

A. 3+3+2
B. 2+3+3
C. 3+2+3
D. 2+4+2

Answer

To determine the arrangement of nuclei in a normal dicot embryo sac, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Structure of the Embryo Sac**:
- The normal dicot embryo sac is a structure that contains a total of seven cells and eight nuclei. It is elongated and has two ends: the chalazal end and the micropyle end.

2. **Identifying the Components**:
- The embryo sac consists of:
- **Three Antipodal Cells**: Located at the chalazal end, each containing one nucleus.
- **One Egg Cell**: Located at the micropyle end, containing one nucleus.
- **Two Synergid Cells**: Also located at the micropyle end, each containing one nucleus.

3. **Counting the Nuclei**:
- The nuclei are arranged as follows:
- **Antipodal Cells**: 3 nuclei (1 in each of the 3 cells)
- **Synergid Cells**: 2 nuclei (1 in each of the 2 cells)
- **Egg Cell**: 1 nucleus
- **Polar Nuclei**: 2 nuclei (these are found in the central cell, which is a polar cell)

4. **Summarizing the Arrangement**:
- Therefore, the arrangement of nuclei in the normal dicot embryo sac can be summarized as:
- 3 (antipodal) + 2 (polar) + 3 (synergids and egg) = 3 + 2 + 3.

5. **Conclusion**:
- The correct arrangement of nuclei in a normal dicot embryo sac is **3 + 2 + 3**.

### Final Answer:
The arrangement of nuclei in a normal dicot embryo sac is **3 + 2 + 3**.

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