If cells kept for sometime in 1M solution of sucrose and 1M solution of NaCl. The water potential `(Psi_(w))` of the cells kept in:

Options

A. Sucrose solution will be greater
B. NaCl solution will be greater
C. Both will be equal
D. Sucrose solution would be lower and NaCl solution would be greater

Answer

To solve the question regarding the water potential of cells kept in 1M solution of sucrose and 1M solution of NaCl, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Water Potential**: Water potential (Ψw) is a measure of the potential energy in water and determines the direction of water movement. It is influenced by solute concentration and pressure.

2. **Define Osmolarity**: Osmolarity refers to the total concentration of solute particles in a solution. It is important to note that different solutes can dissociate into different numbers of particles in solution.

3. **Analyze the Solutions**:
- **Sucrose Solution**: Sucrose does not dissociate in solution; therefore, a 1M sucrose solution has an osmolarity of 1 Osm/L.
- **NaCl Solution**: Sodium chloride (NaCl) dissociates into two ions (Na⁺ and Cl⁻) when dissolved in water. Thus, a 1M NaCl solution has an osmolarity of 2 Osm/L.

4. **Compare Osmolarity**: Since the osmolarity of NaCl (2 Osm/L) is greater than that of sucrose (1 Osm/L), the NaCl solution has a higher concentration of solute particles.

5. **Effect on Water Potential**:
- The presence of solute decreases the water potential. Therefore, the water potential of the NaCl solution will be lower than that of the sucrose solution because it has a higher osmolarity (more solute particles).
- Conversely, the sucrose solution, having a lower osmolarity, will have a higher water potential.

6. **Conclusion**: Based on the analysis, the water potential of the cells kept in the sucrose solution will be greater than that of the cells kept in the NaCl solution.

### Final Answer:
The correct option is **A. Sucrose solution will have greater water potential**.

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