`{:(CH_(2)-O-CO-C_(15)H_(31)),("|"),(CH-O-CO-C_(17)H_(33)),("|"),(CH_(2)-O-CO-C_(17)H_(35)):}`
This neutral lipid is called as

Options

A. `alpha` - plamito, `beta` - oleo, `alpha^(1)`- stearin
B. `alpha` - oleo, `beta` - palmito, `alpha^(1)`-stearin
C. `alpha` - stearo, `beta` - oleo, `alpha^(1)` - palmitin
D. `alpha` - palmito, `beta` - oleo, `gamma` - stearin

Answer

To identify the neutral lipid based on the given structure, we can follow these steps:

### Step 1: Analyze the Given Structure
The structure provided consists of three components:
1. **(CH₂-O-CO-C₁₅H₃₁)**
2. **(CH-O-CO-C₁₇H₃₃)**
3. **(CH₂-O-CO-C₁₇H₃₅)**

### Step 2: Identify Each Component
- The first component **(CH₂-O-CO-C₁₅H₃₁)** corresponds to a fatty acid known as **Palmitic Acid** (C₁₅H₃₁).
- The second component **(CH-O-CO-C₁₇H₃₃)** corresponds to **Oleic Acid** (C₁₇H₃₃).
- The third component **(CH₂-O-CO-C₁₇H₃₅)** corresponds to **Stearic Acid** (C₁₇H₃₅).

### Step 3: Determine the Positions of the Fatty Acids
- The first fatty acid (Palmitic Acid) is in the **alpha position**.
- The second fatty acid (Oleic Acid) is in the **beta position**.
- The third fatty acid (Stearic Acid) is in the **alpha 1 position**.

### Step 4: Combine the Identified Components
Based on the identified fatty acids and their positions, we can conclude that the neutral lipid is a type of glycerolipid, specifically a triacylglycerol (triglyceride) composed of:
- Alpha Palmitic Acid
- Beta Oleic Acid
- Alpha 1 Stearic Acid

### Step 5: Conclusion
Thus, the neutral lipid represented by the given structure is called **"Triacylglycerol"** or **"Triglyceride"**.

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