100g of ethylene undergo polymerization completely, then the weight of polyethylene obtained is

Options

A. 100 gm
B. `lt 1000 gm`
C. `gt 1000 gm`
D. 500 gm

Answer

To solve the problem of determining the weight of polyethylene obtained from 100g of ethylene undergoing polymerization, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Monomer**: The monomer for polyethylene is ethylene (C2H4).

2. **Determine the Molecular Weight of Ethylene**:
- The molecular formula of ethylene is C2H4.
- The atomic mass of Carbon (C) is approximately 12 g/mol and Hydrogen (H) is approximately 1 g/mol.
- Therefore, the molecular weight of ethylene (C2H4) = (2 × 12) + (4 × 1) = 24 + 4 = 28 g/mol.

3. **Calculate the Moles of Ethylene**:
- Using the formula:
\[ \text{Moles of Ethylene} = \frac{\text{Mass}}{\text{Molecular Weight}} = \frac{100 \text{ g}}{28 \text{ g/mol}} \approx 3.57 \text{ moles} \]

4. **Polymerization Process**:
- During polymerization, ethylene molecules combine to form polyethylene. The reaction does not lose any mass; thus, the total mass of the product (polyethylene) will be equal to the mass of the reactants (ethylene).

5. **Weight of Polyethylene**:
- Since 100g of ethylene is completely converted into polyethylene, the weight of polyethylene obtained will also be 100g.

### Final Answer:
The weight of polyethylene obtained is **100g**.

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