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Hydrogen of vegetable ghee at 250^(@)C r...

Hydrogen of vegetable ghee at `250^(@)C` reduces pressure of `H_(2)` from 2 atm to 1.2 atm in 30 minutes. The rate of reaction in terms of molarity per second is

A

`1.03xx10^(-6)`

B

`1.03xx10^(-5)`

C

`1.03xx10^(-7)`

D

`1.03xx10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
B
`r=(2-1.2)/30=(0.8/(60x30))xx1/(0.0821xx523)=1.03xx10^(-5)`M/sec
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