A line in Lyman series of hydrogen atom has a wavelength of `1.03xx10^(-7)m` . What is the initial energy level of the electron ?

If an electron in a hydrogen atom is moving with a kinetic energy of 5.45 xx10^(-19) j then what will be the energy level for this electron ?

The first line of the lyman series in a hydrogen spectrum has a wavelength of 1210 Å. The corresponding line of a hydrogen like atom of Z=11 is equal to

The first line of the lyman series in a hydrogen spectrum has a wavelength of 1210 Å. The corresponding line of a hydrogen like atom of Z=11 is equal to

Find longest wavelength in Lyman series of hydrogen atom spectrum

The longest wavelength of the Lyman series for hydrogen atom is the same as the wavelength of a certain line in the spectrum of He^+ when the electron makes a trensiton from n rarr 2 . The value of n is

If the wavelength of alpha -line of Lyman series in hydrogen atom is lambda , find the wavelength of beta - line of Paschen series.

The wavelength of the first line of Lyman series in hydrogen atom is 1216 . The wavelength of the first line of Lyman series for 10 times ionized sodium atom will be added

The wavelength of the first line of Lyman series in hydrogen atom is 1216 . The wavelength of the first line of Lyman series for 10 times ionized sodium atom will be added

The K_(alpha) X-rays of moylydenum has a wavelength of 71xx10^(-12)m . If the energy of molybdenum atom with molybdenum atom when an L-electron removed is (hc=12.42xx10^(-7)eV)

The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 A^(@) . The wavelength of the second spectral line in the Balmer series of singly - ionized helium atom is