The Lyman series occurs between 91.2 nm and 121.6 nm , the Balmer series occurs between 364.7 nm and 656.5 nm and the Paschen series occurs between 820.6 nm and 1876 nm, Identify the spectral regions to which these wavelengths correspond .

Find the ratio between the wavelength of the most energetic' spectral lines in the Balmer and Paschen series of the hydrogen spectrum.

A source emitting light of wavelengths 480 nm and 600 nm is used in a double slit interference experiment. The separation between the slits is 0.25 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths.

The shortest wavelength in Lyman series is 91.2 nm. The longest wavelength of the series is

White light is a mixture of light of wavelengths between 400 nm and 700 nm. If this light goes through water (mu = 1.33) what are the limits of the wavelength there ?

Wavelength of the first line of balmer seris is 600 nm. The wavelength of second line of the balmer series will be

Find the wavelength in a hydrogen spectrum between the range 500nm to 700nm

Assertion (A) : Limiting line is the balmer series has a wavelength of 364.4 nm Reason (R ) : Limiting line is obtained for a jump electron from n = infty

A beam of light consisting of two wavelengths 650 nm and 520 nm is used to obtain interference fringes in a Young's double slit experiment. (a) Find the distance of the third bright fringe on the screen from the central maximum for the wavelength 650 nm . (b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the slits is 2 mm and the distance between the plane of the slits and screen is 120 cm .

The third line of the Balmer series spectrum of a hydrogen-like ion of atomic number Z equals to 108.5 nm . The binding energy of the electron in the ground state of these ions is E_(n) . Then

The wavelength of the first line in the balmer series is 656 nm .Calculate the wavelength of the second line and the limiting line in the balmer series