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When electron falls from a higher energy...

When electron falls from a higher energy to a lower energy level the difference in the energies appears in the form of

A

`lambda = (h)/(m v)`

B

`m v r = (nh)/(2pi)`

C

`upsilon = (Delta E)/(h)`

D

`upsilon = (h)/(Delta E)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, "When an electron falls from a higher energy level to a lower energy level, the difference in the energies appears in the form of," we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Energy Levels**: - In an atom, electrons occupy specific energy levels or shells around the nucleus. These energy levels are quantized, meaning electrons can only exist in certain allowed states. 2. **Electron Transition**: - When an electron transitions from a higher energy level (let's say n1) to a lower energy level (n2), it loses energy. This transition is a fundamental concept in atomic structure. 3. **Energy Difference**: - The energy difference (ΔE) between these two levels can be calculated using the formula: \[ \Delta E = E_{n1} - E_{n2} \] - Here, \(E_{n1}\) is the energy of the higher level and \(E_{n2}\) is the energy of the lower level. 4. **Emission of Energy**: - The energy lost by the electron during this transition is emitted in the form of electromagnetic radiation. This radiation is often observed as light. 5. **Relation to Frequency**: - The energy of the emitted radiation can also be expressed in terms of its frequency (ν) using Planck's equation: \[ \Delta E = h \nu \] - Where \(h\) is Planck's constant. 6. **Conclusion**: - Therefore, the difference in energy when an electron falls from a higher to a lower energy level appears in the form of light (or electromagnetic radiation). ### Final Answer: The difference in energy appears in the form of **light**.
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