Home
Class 11
CHEMISTRY
The de-Broglie equation treats an electr...

The de-Broglie equation treats an electron to be

A

a particle

B

a wave

C

ray

D

both (1) and (2)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding what the de-Broglie equation treats an electron to be, we can follow these steps: ### Step 1: Understand the de-Broglie Equation The de-Broglie equation is given by: \[ \lambda = \frac{h}{mv} \] where: - \(\lambda\) is the wavelength, - \(h\) is Planck's constant, - \(m\) is the mass of the electron, and - \(v\) is the velocity of the electron. ### Step 2: Recognize the Dual Nature of Matter The de-Broglie equation suggests that particles such as electrons exhibit both wave-like and particle-like properties. This concept is known as the dual nature of matter. ### Step 3: Identify the Implication of the Equation According to the de-Broglie hypothesis, every moving particle or object has an associated wavelength. For electrons, this means that they can behave like waves under certain conditions, which is a fundamental principle in quantum mechanics. ### Step 4: Conclude the Answer Therefore, the de-Broglie equation treats an electron as having dual nature, meaning it behaves both as a particle and as a wave. ### Final Answer The de-Broglie equation treats an electron to be both a particle and a wave. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The de-Broglie equation suggests that an electron has

The De-Brogli wave is

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de-Broglie wavlength of an electron emitted fromt the ground state of an H-atom after the absoprtion of a photon quals (1)/(2) of the de-Broglie wavelength when it was in orbit. The energy of the photon abserobed is

Which is the de-Broglie equation?

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

In experiment of Davisson-Germer, emitted electron from filament is accelerated through voltage V then de-Broglie wavelength of that electron will be _______m.

The de-Broglie wavelength of an electron in 4th orbit is (where, r=radius of 1st orbit)

The de-Broglie wavelength of an electron in 4th orbit is (where, r=radius of 1st orbit)

Calculate the de-Broglie wavelength of an electron beam accelerated through a potential difference of 60 V.