The magnetic quantum number m for the outermost electron in the Na atom,is

Options

A. 1
B. 0
C. 2
D. `-1`

Answer

To find the magnetic quantum number (m) for the outermost electron in a sodium (Na) atom, we can follow these steps:

### Step-by-Step Solution:

1. **Determine the Atomic Number of Sodium:**
- Sodium (Na) has an atomic number of 11. This means it has 11 electrons.

2. **Write the Electron Configuration:**
- The electron configuration for sodium is:
\[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^1 \]
- Here, the outermost electron is in the 3s orbital.

3. **Identify the Principal Quantum Number (n):**
- The principal quantum number (n) for the outermost electron in the 3s orbital is 3.

4. **Determine the Azimuthal Quantum Number (l):**
- For the s orbital, the azimuthal quantum number (l) is 0.

5. **Find the Magnetic Quantum Number (m):**
- The magnetic quantum number (m) can take values from \(-l\) to \(+l\), including 0. Since \(l = 0\) for the s orbital:
\[ m = 0 \]

6. **Conclusion:**
- Therefore, the magnetic quantum number (m) for the outermost electron in the sodium atom is:
\[ m = 0 \]

### Final Answer:
The magnetic quantum number (m) for the outermost electron in the sodium atom is **0**.

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