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The number of unpaired electrons in 1s^(...

The number of unpaired electrons in `1s^(2) 2s^(2) 2p^(3)` is

A

1

B

2

C

3

D

5

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of unpaired electrons in the electronic configuration `1s^(2) 2s^(2) 2p^(3)`, we can follow these steps: ### Step 1: Identify the Electron Configuration The given electron configuration is `1s^(2) 2s^(2) 2p^(3)`. This indicates the distribution of electrons in the various atomic orbitals. ### Step 2: Fill the Orbitals 1. **1s Orbital**: The `1s` orbital can hold a maximum of 2 electrons. In this case, it has `2` electrons (1s²), which means both are paired. 2. **2s Orbital**: The `2s` orbital also holds a maximum of 2 electrons. Here, it has `2` electrons (2s²), which are also paired. 3. **2p Orbital**: The `2p` orbital can hold a maximum of 6 electrons. In this case, it has `3` electrons (2p³). According to Hund's rule, these electrons will occupy separate orbitals before pairing up. Thus, each of the three electrons will occupy one of the three available p orbitals (2p_x, 2p_y, 2p_z) singly. ### Step 3: Count the Unpaired Electrons - In the `1s` orbital: 0 unpaired electrons (2 paired) - In the `2s` orbital: 0 unpaired electrons (2 paired) - In the `2p` orbital: 3 unpaired electrons (each in separate orbitals) ### Conclusion Adding the unpaired electrons from all orbitals, we find: - Total unpaired electrons = 0 (from 1s) + 0 (from 2s) + 3 (from 2p) = **3 unpaired electrons**. Thus, the answer is **3**.
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Knowledge Check

  • The electronic configuration of an element is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(3) . What is the atomic number of the element which is just below the above element in the periodic table ? 49 31 34 33

    A
    49
    B
    31
    C
    34
    D
    33

  • The electronic configuration of carbon is 1s^(2) 2s^(2) 2p^(2) . There are 12 electrons in C_(2) . The correct electronic configuration of C_(2) molecule is

    A
    `(sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi2p_(x)^(2))`
    B
    `(sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(pi2p_(x)^(2)=pi2p_(y)^(2))`
    C
    `(sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(sigma2p_(z)^(2))(pi2p_(x)^(1)=pi2p_(y)^(1))`
    D
    `(sigma1s^(2))(sigma^(**)1s^(2))(sigma2s^(2))(sigma^(**)2s^(2))(pi2p_(x)^(2)=pi2p_(y)^(1))`

  • What will be the bond order of the species with electronic configuration 1s^(2) 2s^(2) 2p^(5) ?

    A
    One
    B
    Two
    C
    Three
    D
    Zero

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