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The charge of an electron is 1.6 xx 10^(...

The charge of an electron is `1.6 xx 10^(-19)` coulombs. What will be the value of charge of `Na^(+)` ion

A

`1.6 xx 10^(-19)C`

B

`3.2 xx 10^(-19)C`

C

`2.4 xx 10^(-19)C`

D

`11 xx 1.6 xx 10^(-19)C`

Text Solution

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The correct Answer is:
To determine the charge of the sodium ion \( Na^+ \), we can follow these steps: ### Step 1: Understand the charge of an electron The charge of an electron is given as \( -1.6 \times 10^{-19} \) coulombs. This value is negative because electrons carry a negative charge. ### Step 2: Determine the charge of the sodium ion The sodium ion \( Na^+ \) is a cation, which means it has a positive charge. Specifically, the \( Na^+ \) ion has lost one electron, which results in a positive charge. ### Step 3: Relate the charges Since the magnitude of the charge of an electron is \( 1.6 \times 10^{-19} \) coulombs, the charge of the sodium ion \( Na^+ \) will be equal in magnitude but opposite in sign to that of an electron. Therefore, the charge of \( Na^+ \) is: \[ \text{Charge of } Na^+ = +1 \times (1.6 \times 10^{-19}) \text{ coulombs} \] ### Step 4: Final value Thus, the charge of the sodium ion \( Na^+ \) is: \[ \text{Charge of } Na^+ = +1.6 \times 10^{-19} \text{ coulombs} \] ### Conclusion The value of the charge of the \( Na^+ \) ion is \( +1.6 \times 10^{-19} \) coulombs. ---
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