An oxide of nitrogen has a molecular weight of 30. Total number of electrons in one molecule of the compound is

Options

A. 15
B. 30
C. 45
D. 60

Answer

To solve the problem of finding the total number of electrons in one molecule of the nitrogen oxide with a molecular weight of 30, we can follow these steps:

### Step 1: Identify the components of the oxide
The question states that we have an oxide of nitrogen. The possible oxides of nitrogen include NO (nitric oxide), N2O (dinitrogen monoxide), NO2 (nitrogen dioxide), and N2O3 (dinitrogen trioxide).

### Step 2: Determine the molecular weight
We are given that the molecular weight of the oxide is 30. We need to find which oxide corresponds to this molecular weight.

### Step 3: Calculate the molecular weights of possible oxides
1. **NO**:
- Nitrogen (N) has an atomic mass of approximately 14.
- Oxygen (O) has an atomic mass of approximately 16.
- Molecular weight of NO = 14 + 16 = 30.

2. **N2O**:
- Molecular weight = (2 × 14) + 16 = 28 + 16 = 44.

3. **NO2**:
- Molecular weight = 14 + (2 × 16) = 14 + 32 = 46.

4. **N2O3**:
- Molecular weight = (2 × 14) + (3 × 16) = 28 + 48 = 76.

From this, we can see that the only oxide of nitrogen with a molecular weight of 30 is NO.

### Step 4: Determine the number of electrons in one molecule of NO
Now that we have established that the oxide is NO, we can find the total number of electrons in one molecule:
- Nitrogen (N) has an atomic number of 7, which means it has 7 electrons.
- Oxygen (O) has an atomic number of 8, which means it has 8 electrons.

### Step 5: Calculate the total number of electrons
Total number of electrons in one molecule of NO = Electrons from Nitrogen + Electrons from Oxygen = 7 + 8 = 15.

### Conclusion
Thus, the total number of electrons in one molecule of the nitrogen oxide (NO) is **15**.