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Consider the following pairs of ions ...

Consider the following pairs of ions
(A) `Sc^(+3)` and `Ti^(+4)` (B) `Mn^(+2)` and `Fe^(+2)`
(C ) `Fe^(+2)` and `Co^(+3)` (D) `Cu^(+)`and `Zn^(+2)`
Among these pairs of ions, isoelectronic pairs would include

A

B, C and D

B

A, C and D

C

A, B and D

D

A, B and C

Text Solution

AI Generated Solution

The correct Answer is:
To determine which pairs of ions are isoelectronic, we need to find out how many electrons each ion has. Isoelectronic ions have the same number of electrons. Let's analyze each pair step by step. ### Step 1: Analyze Pair (A) Sc³⁺ and Ti⁴⁺ - **Scandium (Sc)** has an atomic number of 21, which means it has 21 electrons. - When Sc loses 3 electrons to form Sc³⁺, it has: \[ 21 - 3 = 18 \text{ electrons} \] - **Titanium (Ti)** has an atomic number of 22, which means it has 22 electrons. - When Ti loses 4 electrons to form Ti⁴⁺, it has: \[ 22 - 4 = 18 \text{ electrons} \] - **Conclusion**: Sc³⁺ and Ti⁴⁺ are isoelectronic because both have 18 electrons. ### Step 2: Analyze Pair (B) Mn²⁺ and Fe²⁺ - **Manganese (Mn)** has an atomic number of 25, which means it has 25 electrons. - When Mn loses 2 electrons to form Mn²⁺, it has: \[ 25 - 2 = 23 \text{ electrons} \] - **Iron (Fe)** has an atomic number of 26, which means it has 26 electrons. - When Fe loses 2 electrons to form Fe²⁺, it has: \[ 26 - 2 = 24 \text{ electrons} \] - **Conclusion**: Mn²⁺ and Fe²⁺ are not isoelectronic because they have 23 and 24 electrons, respectively. ### Step 3: Analyze Pair (C) Fe²⁺ and Co³⁺ - **Iron (Fe)** has already been established to have 24 electrons when in the Fe²⁺ state. - **Cobalt (Co)** has an atomic number of 27, which means it has 27 electrons. - When Co loses 3 electrons to form Co³⁺, it has: \[ 27 - 3 = 24 \text{ electrons} \] - **Conclusion**: Fe²⁺ and Co³⁺ are isoelectronic because both have 24 electrons. ### Step 4: Analyze Pair (D) Cu⁺ and Zn²⁺ - **Copper (Cu)** has an atomic number of 29, which means it has 29 electrons. - When Cu loses 1 electron to form Cu⁺, it has: \[ 29 - 1 = 28 \text{ electrons} \] - **Zinc (Zn)** has an atomic number of 30, which means it has 30 electrons. - When Zn loses 2 electrons to form Zn²⁺, it has: \[ 30 - 2 = 28 \text{ electrons} \] - **Conclusion**: Cu⁺ and Zn²⁺ are isoelectronic because both have 28 electrons. ### Final Conclusion The pairs that are isoelectronic are: - Pair (A): Sc³⁺ and Ti⁴⁺ - Pair (C): Fe²⁺ and Co³⁺ - Pair (D): Cu⁺ and Zn²⁺ Thus, the correct answer is that pairs A, C, and D are isoelectronic.
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