The product formed in the reaction `BCl_3 + H_2 O to `

Options

A. `H_3 BO_3 + HCl`
B. `BrO_3 + HOCl`
C. `B_2 H_6 + HCl`
D. No reaction

Answer

To determine the product formed in the reaction between boron trichloride (BCl₃) and water (H₂O), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are:
- Boron trichloride (BCl₃)
- Water (H₂O)

### Step 2: Identify the Reaction
When BCl₃ reacts with water, it undergoes hydrolysis. During this reaction, BCl₃ reacts with water to form boric acid (H₃BO₃) and hydrochloric acid (HCl).

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction is:
\[ BCl_3 + 3 H_2O \rightarrow H_3BO_3 + 3 HCl \]

### Step 4: Check the Balancing of the Equation
Now, let's check if the equation is balanced:
- **Boron (B)**: 1 on both sides
- **Chlorine (Cl)**: 3 on the left (from BCl₃) and 3 on the right (from 3 HCl)
- **Hydrogen (H)**: 6 on the left (from 3 H₂O) and 6 on the right (3 from H₃BO₃ and 3 from 3 HCl)
- **Oxygen (O)**: 3 on both sides (3 from 3 H₂O and 3 from H₃BO₃)

Since all elements are balanced, the equation is correct.

### Step 5: Identify the Products
The products formed in the reaction are:
- Boric acid (H₃BO₃)
- Hydrochloric acid (HCl)

### Conclusion
The product formed in the reaction between BCl₃ and H₂O is:
\[ H_3BO_3 + 3 HCl \]