The compound formed when diborane reacts with trimethyl amine is

Options

A. `B_2 (CH_3)_6`
B. `BH_3. N (CH_3)_3`
C. `B_3 B_3 H_6`
D. `B_2 H_2 (CH_3)_4`

Answer

To determine the compound formed when diborane (B2H6) reacts with trimethylamine (N(CH3)3), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are diborane (B2H6) and trimethylamine (N(CH3)3).

### Step 2: Understand the Reaction
Diborane is a compound that contains boron and hydrogen, while trimethylamine is an amine that has three methyl groups attached to a nitrogen atom. When these two compounds react, they form a complex.

### Step 3: Write the Reaction
The reaction can be represented as:
\[ \text{B}_2\text{H}_6 + 2 \text{N(CH}_3\text{)}_3 \rightarrow 2 \text{BH}_3\cdot\text{N(CH}_3\text{)}_3 \]

### Step 4: Identify the Product
The product formed from this reaction is a complex where diborane interacts with trimethylamine. The resulting compound is:
\[ \text{BH}_3\cdot\text{N(CH}_3\text{)}_3 \]

### Step 5: Conclusion
Thus, the compound formed when diborane reacts with trimethylamine is:
\[ \text{BH}_3\cdot\text{N(CH}_3\text{)}_3 \]

### Final Answer
The compound formed when diborane reacts with trimethylamine is **trimethylamine-borane (BH3-N(CH3)3)**.

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