Write the reaction products of 2-pentene when oxidised with acidified potassium permanganate at `100^(@)C`.

Explanation

To determine the reaction products of 2-pentene when oxidized with acidified potassium permanganate at 100°C, we will follow these steps:

### Step 1: Identify the structure of 2-pentene
2-pentene is an alkene with the following structure:
\[ \text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_3 \]
This means that the double bond is between the second and third carbon atoms.

### Step 2: Understand the reaction conditions
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