Ethene on treating with bromine in presence of sodium chloride forms a mixture of `CH_(2)ClCH_(2)Br and CH_(2)BrCH_(2)Br`. Give reason.

Explanation

To understand why ethene reacts with bromine in the presence of sodium chloride to form a mixture of products, we can break down the reaction step by step.

### Step 1: Identify the Reactants
Ethene (C₂H₄) is the starting material. It has a double bond between the two carbon atoms:
\[ \text{H}_2C=CH_2 \]

### Step 2: Reaction with Bromine
When ethene is treated with bromine (Br₂), the double bond opens up to allow the addition of bromine across the double bond. The bromine molecule can be represented as:
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