The reducing agents commonly used for the reduction of alkyl halides to get alkanes are

Options

A. `Zn-CH_(3)COOH`
B. `Zn-Cu//C_(2)H_(5)OH`
C. `Na-C_(2)H_(5)OH`
D. All the above

Answer

To answer the question regarding the reducing agents commonly used for the reduction of alkyl halides to form alkanes, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Alkyl Halides**: Alkyl halides are organic compounds containing carbon, hydrogen, and halogen atoms. The general formula is R-X, where R is an alkyl group and X is a halogen (like Cl, Br, or I).

2. **Reduction Process**: The reduction of alkyl halides involves the removal of the halogen atom and the addition of hydrogen to the carbon atom. This process converts the alkyl halide into an alkane.

3. **Common Reducing Agents**:
- **Zinc and Acetic Acid (Zn/CH3COOH)**: This combination can reduce alkyl halides to alkanes. For example, methyl chloride (CH3Cl) can be reduced to methane (CH4) using this method.
- **Zinc with Copper and Ethanol (Zn/Cu in C2H5OH)**: This method also effectively reduces alkyl halides. For instance, two moles of methyl chloride can react with zinc in the presence of copper to form ethane (C2H6).
- **Sodium in Ethanol (Na in C2H5OH)**: Sodium can also serve as a reducing agent. For example, two moles of methyl bromide (CH3Br) can react with sodium in ethanol to produce ethane and sodium bromide (NaBr).

4. **Conclusion**: All the mentioned reducing agents (Zn with acetic acid, Zn with copper and ethanol, and sodium in ethanol) are commonly used for the reduction of alkyl halides to alkanes.

5. **Final Answer**: Therefore, the correct answer is that all of the mentioned options are reducing agents commonly used for the reduction of alkyl halides to alkanes.