`CH_(2)=CH_(2)+O_(3)underset(H_(2)O)overset(Zn)rarrXoverset("Reduction")rarrY.Y` is

Options

A. `CH_(4)`
B. `C_(2)H_(5)OH`
C. `CH_(3)OH`
D. `HCOH`

Answer

To solve the question step by step, we will analyze the reaction of ethene (CH₂=CH₂) with ozone (O₃) and the subsequent reduction process.

### Step 1: Identify the Reactants
The reactant in this reaction is ethene (CH₂=CH₂), which is an alkene with a double bond between the two carbon atoms.

**Hint:** Look for the structure of ethene and identify the functional groups present.

### Step 2: Reaction with Ozone
When ethene reacts with ozone (O₃), it undergoes ozonolysis. This reaction leads to the formation of an ozonide intermediate.

**Hint:** Remember that ozonolysis involves breaking the double bond and forming an intermediate compound.

### Step 3: Formation of Ozonide
The ozonide formed from the reaction of ethene and ozone can be represented as an unstable compound that will further decompose in the presence of water and zinc.

**Hint:** Consider the role of zinc and water in the reaction; they help in breaking down the ozonide.

### Step 4: Decomposition of Ozonide
In the presence of zinc and water (H₂O), the ozonide decomposes to yield two molecules of formaldehyde (HCHO) and hydrogen peroxide (H₂O₂).

**Hint:** Focus on the products formed from the ozonide decomposition.

### Step 5: Reduction of Formaldehyde
The formaldehyde (HCHO) can undergo further reduction. In this case, the reduction of formaldehyde leads to the formation of methanol (CH₃OH).

**Hint:** Think about what happens during the reduction process and what products are typically formed.

### Final Answer
Thus, the final product Y after the reduction of formaldehyde is methanol (CH₃OH).

**Conclusion:** The answer to the question is Y = CH₃OH (methanol).

### Summary of Steps
1. Identify the reactant (ethene).
2. React with ozone to form an ozonide.
3. Decompose the ozonide in the presence of zinc and water to yield formaldehyde.
4. Reduce formaldehyde to form methanol.