What are X and Y in the reaction?
`C_(2)H_(4)+H_(2)SO_(4)overset(80^(@)C)rarrXunderset(Delta)overset(H_(2)O)rarrY`

Options

A. `C_(2)H_(6),C_(2)H_(5)OH`
B. `C_(2)H_(4),C_(2)H_(6)SH`
C. `C_(2)H_(2)OSO_(3)H,C_(2)H_(5)OH`
D. `C_(2)H_(2),CH_(3)CHO`

Answer

To determine the compounds X and Y in the reaction of ethylene (C₂H₄) with sulfuric acid (H₂SO₄) at 80°C, we can break down the reaction step by step.

### Step 1: Reaction of C₂H₄ with H₂SO₄
When ethylene (C₂H₄) reacts with sulfuric acid (H₂SO₄), the double bond in ethylene opens up and the sulfuric acid adds across the double bond. The reaction can be represented as follows:

\[ C_2H_4 + H_2SO_4 \rightarrow C_2H_5OSO_3H \]

In this step, ethylene reacts with sulfuric acid to form ethyl hydrogen sulfate (C₂H₅OSO₃H).

### Step 2: Identify X
From the above reaction, we can identify:
- **X = C₂H₅OSO₃H (ethyl hydrogen sulfate)**

### Step 3: Hydrolysis of X
Next, the ethyl hydrogen sulfate (X) undergoes hydrolysis when it reacts with water (H₂O) in the presence of heat. The reaction can be represented as follows:

\[ C_2H_5OSO_3H + H_2O \rightarrow C_2H_5OH + H_2SO_4 \]

In this step, ethyl hydrogen sulfate reacts with water to produce ethanol (C₂H₅OH) and regenerate sulfuric acid (H₂SO₄).

### Step 4: Identify Y
From the hydrolysis reaction, we can identify:
- **Y = C₂H₅OH (ethanol)**

### Final Answer
Thus, the compounds X and Y in the reaction are:
- **X = C₂H₅OSO₃H (ethyl hydrogen sulfate)**
- **Y = C₂H₅OH (ethanol)**