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C(2)H(5)Cloverset(AlcKOH)rarr Product. ...

`C_(2)H_(5)Cloverset(AlcKOH)rarr` Product.
This reaction is known as

A

hydrohalogenation

B

dehydrohalogenation

C

halogenation

D

dehalogenation

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of C₂H₅Cl with alcoholic KOH, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactant is C₂H₅Cl, which is ethyl chloride, and the reagent is alcoholic KOH (potassium hydroxide in alcohol). 2. **Understand the Reaction Type**: The reaction involves the elimination of a hydrogen atom and a halogen atom (in this case, chlorine) from the ethyl chloride. This process is known as dehydrohalogenation. 3. **Write the Reaction**: The reaction can be represented as: \[ \text{C}_2\text{H}_5\text{Cl} + \text{KOH (alc)} \rightarrow \text{C}_2\text{H}_4 + \text{KCl} + \text{H}_2\text{O} \] Here, ethylene (C₂H₄) is formed along with potassium chloride (KCl) and water (H₂O). 4. **Product Formation**: The product formed is ethylene (C₂H₄), which is an alkene. The chlorine atom is removed from the ethyl chloride, and a hydrogen atom is also removed, leading to the formation of a double bond in the product. 5. **Conclusion**: Therefore, the reaction of C₂H₅Cl with alcoholic KOH results in the formation of ethylene and is classified as a dehydrohalogenation reaction. ### Final Answer: The product is C₂H₄ (ethylene), and this reaction is known as **dehydrohalogenation**. ---
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