Amount of `CO_2` abosorbed by plant to produce 180 gm of glucose

Options

A. 216 gm
B. 264 gm
C. 192 gm
D. 108 gm

Answer

To solve the question of how much CO₂ is absorbed by plants to produce 180 grams of glucose, we can follow these steps:

### Step 1: Understand the Chemical Equation
The process of photosynthesis can be summarized by the equation:
\[ 6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2 \]
This equation shows that 6 molecules of carbon dioxide (CO₂) are used to produce 1 molecule of glucose (C₆H₁₂O₆).

### Step 2: Determine the Molar Mass of Glucose
The molar mass of glucose (C₆H₁₂O₆) can be calculated as follows:
- Carbon (C): 12 g/mol × 6 = 72 g/mol
- Hydrogen (H): 1 g/mol × 12 = 12 g/mol
- Oxygen (O): 16 g/mol × 6 = 96 g/mol

Adding these together:
\[ 72 + 12 + 96 = 180 \text{ g/mol} \]
This confirms that 180 grams of glucose corresponds to 1 mole of glucose.

### Step 3: Calculate the Amount of CO₂ Required
According to the balanced equation, 6 moles of CO₂ are required to produce 1 mole of glucose. Therefore, for 1 mole of glucose (180 grams), we need:
\[ 6 \text{ moles of } CO_2 \]

### Step 4: Determine the Molar Mass of CO₂
The molar mass of carbon dioxide (CO₂) is calculated as follows:
- Carbon (C): 12 g/mol
- Oxygen (O): 16 g/mol × 2 = 32 g/mol

Adding these together:
\[ 12 + 32 = 44 \text{ g/mol} \]

### Step 5: Calculate the Total Mass of CO₂
Since we need 6 moles of CO₂, we can calculate the mass:
\[ 6 \text{ moles} \times 44 \text{ g/mol} = 264 \text{ grams} \]

### Conclusion
Thus, the amount of CO₂ absorbed by plants to produce 180 grams of glucose is **264 grams**.