Home
Class 12
CHEMISTRY
To convert 1 litre of 1.123N solution of...

To convert 1 litre of 1.123N solution of an acid into 1N solution, how much volume of water should be added ?

Text Solution

AI Generated Solution

To solve the problem of converting a 1 liter of 1.123N solution of an acid into a 1N solution, we can follow these steps: ### Step 1: Understand the given values - Initial Normality (N1) = 1.123 N - Initial Volume (V1) = 1 L - Final Normality (N2) = 1 N - Final Volume (V2) = ? ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution of acid having 62% by mass of acid has specific gravity of 1.8 g. If the solution is to be diluted to attain a specific gravity of 1.2 then what volume of water should be added to 100 ml of this solution?

1.325 g of anhydrous sodium carbonate are dissolved in water and the solution made up to 250 mL. On titration, 25 mL of this solution neutralise 20 mL of a solution of sulphuric acid. How much water should be added to 450 mL of this acid solution to make it exactly N/12 ?

A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If there are 640 litres of the 8% solution, how many litres of 2% solution will have to be added?

When 100 mL of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?

pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litre solution of pH=6 (solution of a strong acid) is added to the 7//3 litres of water.What is the pH of resulting solution? Neglect the common ion effect on H_(2)O .

A 1 litre solution of pH=1 diluted upto 10 times.What volume of a solutions with pH =2 is to be added in diluted solution so that final pH remains '2'.

30 ml of N/10 HC1 is required to neutralize 50 ml of a sodium carbonate solution. What volume of water (in ml) must be added to 30 ml of Na_2 CO_3 solution so that the final solution has concentration N/50?

pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litres solution of pH=4 (solution of a strong acid ) is added to the 7//3 litres of water.What is the pH of resulting solution?

What is the pH of 1 M solution of acetic acid ? To what volume one litre of this solution be diluted so that pH of the resulting solution will be twice of the original value ? (K_(a)=1.8xx10^(-5))