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An X-ray beam (lambda = 70.9 p m) was sc...

An X-ray beam `(lambda = 70.9 p m)` was scattered by a crystalline solid. The angle `(2theta)` of the diffraction for a second order reflection is `14.66^(0)`. Calculate the distance between parallel planes of atoms of the crystalline solid.

Text Solution

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The Bragg’s equation is given as, `nlambda. = 2d sin theta`
n = order of reflection = 2
`lambda` = wave length of X-rays = `7.09 xx 10^(-11)m`
`theta` = Angle of reflection = `7.33^(@)`
d = distance between parallel planes Distance between parallel planes (d) = `(lambda)/(sin theta)=(7.09xx10^(-11))/(sin 7.33^(@)) d= 6.18 xx10^(-10)m `
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