The packing fraction of a simple cubic structure is `(pi)/(6)`. Prove.

Explanation

In a simple cube, the face edge length, a = 2r Number of atoms present in one unit cell = 1 Packing fraction =
`("volume occupied by atoms" )/("volume of the unit cell" ) =(4/3pir^(3))/(a^(3))=4/3(pir^(3))/(2r)^(3)=(pi)/(6)`