Home
Class 12
CHEMISTRY
Atomic weight of silver is 107.8. Silver...

Atomic weight of silver is 107.8. Silver crystallises in fcc lattice with edge length of unit cell is 4.086 Ao. Calculate the density of unit cell of silver and radius of silver atom. 

Text Solution

Verified by Experts

`1.05 xx10^(4) KGM^(-3) ,2.574 a^(@)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Silver crystallises in fcc latice. If edge length of the unit cell is 4.077xx10^(-8)cm , then calculate the radius of silver atom.

If atomic radius of barium is 2.176Å and it crystallises in b.c.c. unit cell, the edge length of unit cell is

The radius of an atom is 100 pm. If this element crystallizes in FCC lattice, the edge length of unit cell is

Silver crystallizes in fcc lattic. If the edge length of the cell is 4.07 xx 10^(-8) cm and density is 10.5 g cm^(-3) . Calculate the atomic mass of silver.

Silver crystallizes in fcc lattic. If the edge length of the cell is 4.07 xx 10^(-8) cm and density is 10.5 g cm^(-3) . Calculate the atomic mass of silver.

Density of silver is 10.5 g cc^(-1) Calculate the edge length of the unit cell of silver.

Silver metal crysatllises with a face centred cubic lattice. The length of the unit cell is found to be 450 pm. Calulate the atomic radius.

Xenon is crystallized in the fcc lattice and the edge of unit length is 620 pm. What is the nearest neighbour distance and radius of xenon atom ?

A metal crystallises with a body-centred cubic lattice. The edge length of the unit cell is 360 pm. Radius of the metal atom is

.A metal crystallises in fcc lattice.If edge length of the cell is 4.07×10^−8 cm and density is 10.5gcm^−3 . Calculate the atomic mass of metal.