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A vessel contains 0.25 moles of Helium a...

A vessel contains 0.25 moles of Helium and 0.15 moles of neon at 298K and 2.4 atmosphere pressure. Calculate the partial pressure of each gas in the mixture.

Text Solution

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Total Pressure .P.=2.4atm
No. of moles of He=0.25
No. of moles of Ne=0.15
Total moles of n=0.25+0.15=0.4
Partial pressure = Total pressure X Mole-fraction
`P_(He) = (n_(He))/(n) xx P = (0,.25)/(0.4) xx 2.4 = 1.5 atm`
`P_(N e) = (n_(N e))/(n) xx P = (0.15)/(0.4) xx 2.4 = 0.9 atm`.
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