Home
Class 11
CHEMISTRY
Find the mass of 7 xx 10^(20) molecules ...

Find the mass of `7 xx 10^(20)` molecules of `H_2`gas.

Text Solution

AI Generated Solution

The correct Answer is:
To find the mass of \( 7 \times 10^{20} \) molecules of \( H_2 \) gas, we can follow these steps: ### Step 1: Calculate the number of moles To find the number of moles of \( H_2 \) gas, we use Avogadro's number, which is \( N_A = 6.022 \times 10^{23} \) molecules/mole. The formula to calculate moles (\( n \)) from the number of molecules (\( N \)) is: \[ n = \frac{N}{N_A} \] Substituting the values: \[ n = \frac{7 \times 10^{20}}{6.022 \times 10^{23}} \] ### Step 2: Perform the calculation Calculating the above expression: \[ n \approx \frac{7}{6.022} \times 10^{20 - 23} = \frac{7}{6.022} \times 10^{-3} \approx 1.16 \times 10^{-2} \text{ moles} \] ### Step 3: Find the molar mass of \( H_2 \) The molar mass of hydrogen gas (\( H_2 \)) is calculated as follows: - The atomic mass of hydrogen (H) is approximately \( 1 \, \text{g/mol} \). - Since \( H_2 \) consists of 2 hydrogen atoms, the molar mass of \( H_2 \) is: \[ \text{Molar mass of } H_2 = 2 \times 1 \, \text{g/mol} = 2 \, \text{g/mol} \] ### Step 4: Calculate the mass Now, we can calculate the mass (\( m \)) using the formula: \[ m = n \times \text{Molar mass} \] Substituting the values we found: \[ m = 1.16 \times 10^{-2} \, \text{moles} \times 2 \, \text{g/mol} = 2.32 \times 10^{-2} \, \text{grams} \] ### Final Answer The mass of \( 7 \times 10^{20} \) molecules of \( H_2 \) gas is approximately: \[ \text{Mass} \approx 2.32 \times 10^{-2} \, \text{grams} \text{ or } 0.0232 \, \text{grams} \] ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A gas jar contains 7.2 xx 10^(20) molecules of NH_(3) gas. Find : weight in grams

A gas jar contains 7.2 xx 10^(20) molecules of NH_(3) gas. Find : number of moles

A gas jar contains 7.2 xx 10^(20) molecules of NH_(3) gas. Find : volume in cm_(3) of ammonia gas at S. T.P. [N = 14, H = 1]

A sample of ethane (C_(2)H_(6)) gas has the same mass a 1.5 xx 10^(20) moleucles of methane (CH_(4)) . How many C_(2)H_(6) . How many C_(2)H_(6) molecules does the sample of gas contain?

A gas cylinder contains 12 xx 10^(24) molecules of oxygen gas. If Avogadro's number is 6 xx 10^(23) . Calculate : The mass of oxygen present in the cylinder.

The molecular mass of a compound is 75 (i) What is the mass of 6.022xx10^(20) molecules , in gm (ii) How many molecules are in its 2.5 mg

A candle is burnt in a beaker until extinguishers itseft. A sample of gaseous mixutre in the beaker contains 6.08 xx 10^(20) molecules of O_(2) , and 0.50 xx 10^(20) molecules of CO_(2) . The total pressure is 734 mm of Hg . The partial pressure of O_(2) would be

A gas cylinder contains 12 xx 10^(24) molecules of oxygen gas. If Avogadro's number is 6 xx 10^(23) . Calculate : The volume of oxygen at S.T.P. present in the cylinder. [O = 16]

A gas cylinder contains 24 xx 10^(24) molecules of nitrogen gas. If Avogadro's number is 6xx10^(23) and the relative atomic mass of nitrogen is 14, calculate: Mass of nitrogen gas in the cylinder.

A gas cylinder contains 24 xx 10^(24) molecules of nitrogen gas. If Avogadro's number is 6xx10^(23) and the relative atomic mass of nitrogen is 14, calculate: Volume of nitrogen at STP in dm.