Home
Class 11
CHEMISTRY
Calculate kinetic energy of 5 moles of N...

Calculate kinetic energy of 5 moles of Nitrogen at `27^@C`.

Text Solution

Verified by Experts

The correct Answer is:
18706.50 J
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the kinetic energy of 5 moles of O_2 " at " 0^@C. (R = 8.31 xx 10^7 " ergs " K^(-1) mol^(-1))

The kinetic enerrgy of 4 mole sof nitrogen gas at 127^(@)C is (R=2" cal "mol^(-1)K^(-1))

Calculate the number of moles in 7g of nitrogen.

Kinetic energy of a molecule is zero at 0^(@)C

Calculate (a) the average kinetic energy of translation of an oxygen molecule at 27^(@) C (b) the total kinetic energy of an oxygen molecule at 27^(@)C (c ) the total kinetic energy in joule of one mole of oxygen at 27^(@) . Given Avogadro's number = 6.02 xx 10^(23) and Boltzmann's constant = 1.38 xx 10^(-23) J//(mol-K) .

If the average kinetic energy of a molecule of hydrogen gas at 300 K is E , then the average kinetic energy of a molecule of nitrogen gas at the same temperature is

Find the kinetic energy of 1 g of nitrogen gas at 77^(@)C . Given R=8.31" J "mol^(-1)K^(-1)

What will be the total kinetic energy of 3 moles of methane at 200^(@)C ?

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

Calculate the average kinetic energy of neon molecule at 27^(@)C . Given k_(B)=1.38xx10^(-23)JK^(-1)