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If the significant figures are more...

If the significant figures are more

A

percentage error is more and accuracy is less

B

percentatge error is less and accuracy is more

C

percentage error is less and accuracy is less

D

percentage error is more and accuracy is more

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding significant figures, percentage error, and accuracy, we can break it down into clear steps: ### Step-by-Step Solution: 1. **Understanding Significant Figures**: - Significant figures are the digits in a number that contribute to its precision. For example, in the number 5.45694, all digits are significant. 2. **Identifying Cases**: - We will consider two cases for the number 5.45694: - Case 1: Using **five significant figures** (5.4569) - Case 2: Using **three significant figures** (5.46) 3. **Rounding Off**: - For Case 1 (five significant figures), we round the last digit: - 5.45694 rounds to **5.4569**. - For Case 2 (three significant figures), we round to: - 5.45694 rounds to **5.46**. 4. **Calculating the Errors**: - **Error in Case 1**: - The original value is 5.45694, and the rounded value is 5.4569. - The error (Δx) = 5.45694 - 5.4569 = **0.00004**. - **Error in Case 2**: - The original value is 5.45694, and the rounded value is 5.46. - The error (Δx) = 5.45694 - 5.46 = **0.00094**. 5. **Comparing Percentage Errors**: - **Percentage Error for Case 1**: - Percentage Error = (Δx / Original Value) * 100 - = (0.00004 / 5.45694) * 100 ≈ **0.000733%**. - **Percentage Error for Case 2**: - Percentage Error = (Δx / Original Value) * 100 - = (0.00094 / 5.45694) * 100 ≈ **0.0172%**. 6. **Conclusion**: - Since the percentage error is smaller when using more significant figures (Case 1), we conclude that: - **More significant figures lead to less percentage error and higher accuracy**. ### Final Answer: - Therefore, the answer is that **when more significant figures are used, the percentage error decreases and accuracy increases**.
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