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In an experiment, a physical quantity is...

In an experiment, a physical quantity is given by `Y=(a^(2)b)/(c^(3))`. The permissible percentage error

A

`((Delta a)/(a)+(Delta b)/(b)+(Delta c)/(c ))xx100`

B

`(2.(Delta a)/(a)+(Delta b)/(b)-(3Delta c)/(c ))xx100`

C

`(2.(Delta a)/(a)+(Delta b)/(b)+(3Delta c)/(c ))xx100`

D

`(2.(Delta a)/(a)-(Delta b)/(b)-(3Delta c)/(c ))xx100`

Text Solution

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The correct Answer is:
To solve the problem of determining the permissible percentage error in the physical quantity \( Y = \frac{a^2 b}{c^3} \), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the formula for \( Y \)**: We have the physical quantity defined as: \[ Y = \frac{a^2 b}{c^3} \] 2. **Understand the concept of errors**: In measurements, we denote the measured values as: - \( a \) is measured as \( a + \Delta a \) - \( b \) is measured as \( b + \Delta b \) - \( c \) is measured as \( c + \Delta c \) where \( \Delta a \), \( \Delta b \), and \( \Delta c \) are the absolute errors in the measurements of \( a \), \( b \), and \( c \) respectively. 3. **Calculate the fractional error in \( Y \)**: The fractional error in \( Y \) can be derived from the formula for \( Y \): - The fractional error due to \( a \) (since \( a \) is squared): \[ \frac{\Delta Y_a}{Y} = 2 \cdot \frac{\Delta a}{a} \] - The fractional error due to \( b \): \[ \frac{\Delta Y_b}{Y} = \frac{\Delta b}{b} \] - The fractional error due to \( c \) (since \( c \) is cubed): \[ \frac{\Delta Y_c}{Y} = 3 \cdot \frac{\Delta c}{c} \] 4. **Combine the fractional errors**: Since \( c \) is in the denominator, its contribution to the error will be negative: \[ \frac{\Delta Y}{Y} = 2 \cdot \frac{\Delta a}{a} + \frac{\Delta b}{b} - 3 \cdot \frac{\Delta c}{c} \] 5. **Convert to percentage error**: The percentage error in \( Y \) is given by: \[ \text{Percentage Error} = \left( \frac{\Delta Y}{Y} \right) \times 100 \] Substituting the expression for fractional error: \[ \text{Percentage Error} = \left( 2 \cdot \frac{\Delta a}{a} + \frac{\Delta b}{b} - 3 \cdot \frac{\Delta c}{c} \right) \times 100 \] 6. **Final expression**: The final expression for the permissible percentage error in \( Y \) is: \[ \text{Percentage Error} = 2 \cdot \frac{\Delta a}{a} \times 100 + \frac{\Delta b}{b} \times 100 - 3 \cdot \frac{\Delta c}{c} \times 100 \]
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