Home
Class 11
PHYSICS
[J. m^(-3)] may be the unit of...

`[J. m^(-3)]` may be the unit of

A

Strain energy density

B

Modulus of Elasticity

C

Both a & b

D

Strain energy

Text Solution

AI Generated Solution

The correct Answer is:
To determine what the unit `[J. m^(-3)]` may represent, we can analyze the options provided and relate them to the definitions of strain energy density, modulus of elasticity, and strain energy. ### Step-by-Step Solution: 1. **Understanding the Unit**: The unit `[J. m^(-3)]` can be interpreted as joules per cubic meter (J/m³). This indicates a quantity that is measured in energy (joules) divided by volume (cubic meters). 2. **Strain Energy Density**: - Strain energy density is defined as the energy stored in a material per unit volume due to deformation. - The formula for strain energy density can be expressed as: \[ \text{Strain Energy Density} = \frac{\text{Energy}}{\text{Volume}} \] - The unit of energy is joules (J), and the unit of volume is cubic meters (m³). - Therefore, the unit of strain energy density is: \[ \text{Unit} = \frac{J}{m^3} = J \cdot m^{-3} \] 3. **Modulus of Elasticity**: - The modulus of elasticity is defined as the ratio of stress (force per unit area) to strain (dimensionless). - Stress is measured in pascals (Pa), where \(1 \, \text{Pa} = 1 \, \text{N/m}^2\). - Therefore, the modulus of elasticity can be expressed as: \[ \text{Modulus of Elasticity} = \frac{\text{Force}}{\text{Area}} = \frac{\text{N}}{m^2} \] - Since \(1 \, \text{N} = 1 \, \text{J/m}\), we can rewrite the modulus of elasticity as: \[ \text{Modulus of Elasticity} = \frac{J/m}{m^2} = \frac{J}{m^3} = J \cdot m^{-3} \] 4. **Strain Energy**: - Strain energy is simply the total energy stored in the material due to deformation, which is measured in joules (J). - It does not have a unit of J/m³ but rather just J. 5. **Conclusion**: - From the analysis, both strain energy density and modulus of elasticity have the unit of \(J/m^3\). - Therefore, the correct answer to the question is that `[J. m^(-3)]` may be the unit of both strain energy density and modulus of elasticity. ### Final Answer: The unit `[J. m^(-3)]` may be the unit of: - **Strain Energy Density** - **Modulus of Elasticity** - **Both A and B** Thus, the correct option is **C: Both A and B**.
Promotional Banner

Similar Questions

Explore conceptually related problems

J Kg^(-1) K^(-1) is the unit of

The S.I unit of a physical quantity is [J.m^(-2)] . The dimensional formula for that quantity is

If the unit of force is 1N, the unit of work done is 10 J and the unit of time is 1 second, the unit of mass is

A calorie is a unit of heat or energy and it equals about 4.2 J, where 1 J = 1 kg m^(2) s^(-2) . Suppose we employ a system of units in which the unit of mass equals alpha kg , the unit of length equals is beta m , the unit of time is gamma s . Show tthat a calorie has a magnitude 4.2 alpha^(-1) beta^(-1) gamma^(2) in terms of the new units.

A calorie is a unit of heat or energy and it equals about 4.2 J, where 1 J = 1 kg m^(2) s^(-2) . Suppose we employ a system of units in which the unit of mass equals alpha kg , the unit of length equals is beta m , the unit of time is gamma s . Show tthat a calorie has a magnitude 4.2 alpha^(-1) beta^(-1) gamma^(2) in terms of the new units.

The calorie is a unit of heat or energy and it equals about 4.2 J where 1J=1kgm^(2)s^(-2) . Suppose we employ a system of units in which the unit of mass equals alpha kg, the unit of length equals beta m and the unit of time is gamma s. Show that the calorie has a magnitude of 4.2alpha^(-1) beta^(-2) gamma^(2) in terms of the new units.

Assertion : Kilowatt hour is the unit of power. Reason: One kilowatt hour is equivalent to 3.6 xx 10^5 J

A non-zero vector vec a is such that its projections along vectors ( hat i+ hat j)/(sqrt(2)),(- hat i+ hat j)/(sqrt(2)) and hat k are equal, then unit vector along vec a is a. (sqrt(2) hat j- hat k)/(sqrt(3)) b. ( hat j-sqrt(2) hat k)/(sqrt(3)) c. (sqrt(2))/(sqrt(3)) hat j+( hat k)/(sqrt(3)) d. ( hat j- hat k)/(sqrt(2))

[(1,3),(-2,4)]+[(11,5),(-6,12)]=K[(3,2),(J,M)] . Find the value of K+J+M.

STATEMENT 1: Two quantities with different dimensions may have same unit. STATEMENT-2 Two quantities with different units may have same dimensions STATEMENT-3 Unitless quantities must be dimensionless too